Q. 49

Pure water vapour is trapped in a vessel of volume 10 cm3. The relative humidity is 40%. The vapour is compressed slowly and isothermally. Find the volume of the vapour at which it will start condensing.

Answer :

Given


Relative humidity= 40%


Initial volume of vapor V1=10cm3=10.





Let saturation vapor pressure be Po


So, initial pressure of vapours= P1=0.4Po


As mentioned in question, final stage comes when vapours start to condense.


When vapor starts to condense, relative humidity becomes 100% and vapor pressure attains the maximum pressure called saturation vapor pressure.


So final pressure of vapor P2=Po


Since the process is isothermal, temperature remains constant throughout. Applying Boyle’s law which states that PV=constant, if temperature is constant.



P1V1=P2V2



the volume of the vapour at which it will start condensing is 410-6m3


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