Q. 444.0( 4 Votes )
Prove that the mechanical energy of a freely falling object in the gravitational field remains constant at every point.
In the figure, the height of the building is h and let the object be at a height x above the ground level.
1: The total energy(E) of the object when it was at the top of the building was potential energy(U)
E = U = mgh
2: The total energy of the object when at a height of x above the ground level is partly kinetic energy (K) and potential energy.
The velocity v of the object is gien by,
As the initial energy is 0,
Now the potential energy is
U = mgx
Hence, the total energy of the object is
E = K + U = mg(h-x) + mgx
E = mgh
Hence, it is proved that the mechanical energy of freely falling on object in gravitational the eld remain constant remains point as x is any arbitrary distance.
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