Answer :
cos6x = 4 cos32x - 3 cos2x
= 4(2cos2x-1)3 - 3(2cos2x-1)
= 4[(2cos2x)3 - 3×(2cos2x)2×1 + 3 × 2 cos2x×1 - 13]-6cos2x + 3
= 32cos6x - 48cos4x + 18cos2x -1
= R.H.S
Hence proved
= 4(2cos2x-1)3 - 3(2cos2x-1)
= 4[(2cos2x)3 - 3×(2cos2x)2×1 + 3 × 2 cos2x×1 - 13]-6cos2x + 3
= 32cos6x - 48cos4x + 18cos2x -1
= R.H.S
Hence proved
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