Q. 335.0( 1 Vote )

Protons having kinetic energy K emerge from an accelerator as a narrow beam. The beam is bent by a perpendicular magnetic field so that it just misses a plane target kept at a distance ℓ in front of the accelerator. Find the magnetic field.

Answer :

Given-
Kinetic energy of proton = K



Distance between the target and the accelerator = l



Therefore, radius of the circular orbit ≤ l



From question it is given that, the beam is bent by a


perpendicular magnetic field, let it be B.




We know-


Now, radius r -




where,


m is the mass of a proton


v= velocity of the particle


B = magnetic force


e= charge on the particle


For a proton, the above equation can be written as-



where r = l


Kinetic energy, K



Substituting the values of v in the equation (1)





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