Answer :

There are two primary alkyl halides having the formulaC4H9Br, They are n - butyl bromide and isobutyl bromide.







Therefore, compound (a) is either n-butyl bromide or isobutyl bromide.


Now, compound (a) reacts with Na metal to give compound (b) of molecular formula, C18H18 which is different from the compound formed when n-butyl bromide reacts with Na metal.


Hence, compound (a) must be isobutyl bromide.


Thus, compound (d) is 2, 5-dimethylhexane.


It is given that compound (a) reacts with alcoholic KOH to give compound (b). Hence, compound (b) is 2-methylpropene.


Also, compound (b) reacts with HBr to give compound (c) which is an isomer of (a). Hence, compound (c) is 2-bromo-2-methylpropane.:


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