# Pressure of 1 g of an ideal gas A at 27°C is found to be 2 bar. When 2 g of another ideal gas B is introduced in the same flask at same temperature the pressure becomes 3 bar. Find a relationship between their molecular masses.

For ideal gas A, the ideal gas equation is given by,

PaV = naRT

Where, Pa and na represent the pressure and number of moles of gas A.

For ideal gas B, the ideal gas equation is given by,

PbV = nbRT

Where,Pa and nb represent the pressure and number of moles of gas B.

[V and T are constants for gases A and B]

Therefore, we have, Where, Ma and Mb are the molecular masses of gases A and B respectively.

Now, we have

Substituting the values

ma = 1 g

Pa = 2 bar

mb = 2 g

Pb = 1 bar.

Given,

(Since total pressure is 3 bar)

Substituting these values in equation we have Thus, a relationship between the molecular masses of A and B is given by

4Ma = Mb

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