Answer :

Let us consider a body moving in uniform motion, then we can plot the velocity-time graph for the motion of the body moving with a constant velocity of 30 km/h, which means that the body will cover a distance of 30 km in1 hour, 60km in 2 hours, 90 km in 3 hours and so on.If we want to know the distance the body has moved between time say t

s = vt

Hence, the distance moved by the body in time (t

= [(30 km/h)(t

= 30 (t

The area under the velocity-time graph gives the distance travelled by the body.

_{1}and t_{2}. We draw perpendiculars from points corresponding to the time t_{1}and t_{2}on the above graph. The two perpendiculars enclose a rectangle ABCD between the graph and the time axis. The sides AB and CD of this rectangle are equal to (t_{2}– t_{1}) while the sides AC and BD are equal to 30 km/h. We know that the distance s covered by a body moving a velocity v, in time t is given bys = vt

Hence, the distance moved by the body in time (t

_{2}– t_{1}) is= [(30 km/h)(t

_{2}– t_{1})h]= 30 (t

_{2}– t_{1}) kmThe area under the velocity-time graph gives the distance travelled by the body.

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