Slope A is the smaller mass line.
The charge of mass and is denoted as “q”. Now showing the variation according to the de-Broglie’s wavelength we get:
is the de-Broglie’s wavelength, m is equivalent to the mass, q is the charge of the particle, v is the velocity of the charged particle.
Therefore, to find the slope of the de-Broglie’s wavelength, the graph (7.1) is depicted as
Hence, the slope of A is greater than B, as mass > because mass and wavelength is inversely proportional to each other and that’s why slope A is mass.
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