Q. 1 B5.0( 4 Votes )

Find the number o

Answer :

Here, p(x) = x —x2 —1


To find the zeros of p(x), consider p(x) = 0


x – x2 – 1 = 0


Taking negative common


x2 – x + 1 = 0


x2 – x + + 1 – = 0


(Adding and subtracting in order to do factorization)


+ = 0


Using the identity: (a– b) 2 = (a2 – 2ab + b2)


= –


The above equation cannot be true as the square of a real number cannot be negative.


No zero exists for p(x).


Hence, the number of zeros of the given polynomial is 0.


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