CH3OH, methanol has hydrogen bonding between its molecules. When acetone is added the hydrogen bonding breaks and new bonds formation takes place, these bond sare not so strong as intermolecular hydrogen bonding i.e. interaction between acetone -methanol is not as strong as the interaction between methanol-methanol and acetone-acetone molecules.
Since the boiling point has reduced the vapor pressure will increase above the liquid solution, which is a positive deviation from Raoult's law.
Thus, at a specific composition methanol-acetone mixture will form minimum boiling azeotrope and will show positive deviation from Raoult’s law.
Thus, Option(i) is the correct answer.
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