Answer :

Given,


Relative speed of child with respect to belt, vbc = 9 km/h


Speed of the belt, v = 4 km/h


Distance between parents, d = 50 m


(a) Speed of the child for stationary observer when he moves in same direction of belt is given by, V = vbc + v


= 9 + 4 = 13 km/h


(b) Speed of the child for stationary observer when he moves in opposite direction of belt is given by, V = vbc – v


= 9 – 4 = 5 km/h


(c) Since, parents are stationary with respect to belt, child speed is same for both. That is vbc = 9 km/h = 2.5 m/s


time taken by child to move towards one of his parents, t =


t = = 20 s


If the motion is viewed in parent’s perspective, answer in (a) and (b) will alter and answer in (C) unaltered. Because, for them child speed is constant and equal to 9 km/h.


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