Answer :

As de Broglie suggested that the wavelength of a matter is associated with its momentum as

Where P is the momentum of matter (mv)

And h is Planck’s constant i.e.

The velocity of an electron following Bohr model is given by

Where Z is the atomic number of hydrogen-like species

And n is the orbit in which the electron is revolving

Speed of electron in 2^{nd} excited state will be

As Z = 1

And n =3

So, momentum in a 2^{nd} excited state will be

P= mv

Therefore then,

Now for 3^{rd} excited state

Speed of electron in a 3^{rd} excited state will be

As Z = 1

And n =4

So, momentum in a 3^{rd} excited state will be

P= mv

So,

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