Q. 234.2( 11 Votes )

# Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds.

Answer :

from the equation of motion

s= ut + at^{2} Distance travelled in 5s,

s = u x 5+ x a x (5)^{2}

s =5u + 25/2 a …….(i)

Similarly, distance travelled in 4s,

s’ =4u +16/2 a

s’ =4u+8a…….(ii)

Distance travelled in the interval between 4^{th} and 5^{th} second=(s-s’)

= (5u +25/2 – 4u +8)

= (u+ a) m

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