Q. 234.2( 11 Votes )

Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds.

Answer :

from the equation of motion

s= ut + at2 Distance travelled in 5s,


s = u x 5+ x a x (5)2


s =5u + 25/2 a …….(i)


Similarly, distance travelled in 4s,


s’ =4u +16/2 a


s’ =4u+8a…….(ii)


Distance travelled in the interval between 4th and 5th second=(s-s’)


= (5u +25/2 – 4u +8)


= (u+ a) m


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