Q. 16 B4.8( 4 Votes )

# Now assume that the straight wire carries a current of 50 A and the loop is moved to the right with a constant velocity, v = 10 m/s.

Calculate the induced emf in the loop at the instant when x = 0.2 m.

Take a = 0.1 m and assume that the loop has a large resistance.

Answer :

The emf induced in the coil is given as:

e = B’ av

e =

substituting the given values in above relation, we get

e =

On calculating, we get

e = 5 × 10^{-5}V

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PREVIOUSObtain an expression for the mutual inductance between a long straight wire and a square loop of side a as shown in Fig. 6.21.NEXTA line charge λ per unit length is lodged uniformly onto the rim of a wheel of mass M and radius R. The wheel has light non - conducting spokes and is free to rotate without friction about its axis (Fig. 6.22). A uniform magnetic field extends over a circular region within the rim. It is given by,B = – B0 k (r ≤ a; a < R)= 0 (otherwise)What is the angular velocity of the wheel after the field is suddenly switched off?

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