Answer :

(a) As the reaction is first order, so the rate equation can be written as:



t=20 minutes, [A]0= 0.400 M, [A]= 0.289 M


So,



0.14114


min-1


(b) Now we have t=100 min, [A]0= 0.400 M and k=0.0163 min-1


So,


0.0163


[A] = 0.078 M


(c) Initial Rate, R = k[N2O5]


= 0.0163 0.400


= 0.00652 M min-1


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Note: In the follChemistry - Exemplar

Which of the follChemistry - Exemplar