Q. 94.4( 36 Votes )

Nitric oxide reac

Answer :

The chemical reaction is,

Initial amount:


Let x amount of Br2 be reacted to attain equilibrium. Then amount of substance left at equilibrium,


2NO (g) + Br2 (g) 2NOBr (g)


Equilibrium amount: 0.087 – 2x 0.0437 – x 2x


Given, equilibrium concentration of NOBr is 0.0518,


i.e, 2x = 0.0518


x = 0.0259


Thus,


Amount of NO at equilibrium = 0.087 - 2 × 0.0259


= 0.0352 mole


Amount of Br2 at equilibrium = 0.0437 – 0.0259


= 0.0178 mole


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