Q. 16 C4.3( 4 Votes )

# <span lang="EN-US

NH3 +Cl2 N2 +NH4Cl

Balanced equation: 8NH3(g) + 3Cl2(g) N2(g) + 6NH4Cl(s)

Explanation:

Step 1: Write the given unbalanced equation

NH3 +Cl2 N2 +NH4Cl

Step 2: Compare the number of atoms of reactants with the number of atoms of products. Step 3: Now, first we consider the element having unequal no. of atoms on both sides. Thus, first let us consider hydrogen atom. If we multiply 4 in the reactant (in NH3) and 3 in product (in NH4Cl), we will get the equal number of atoms as in both the sides. Step 4: Write the resulting equation:

4NH3 +Cl2 N2 + 3NH4Cl

Step 5: Now check whether the equation is balanced or not by comparing the atoms We find that the equation is not balanced yet. As the number of chlorine and nitrogen atoms are unequal on the two sides.

First balance the chlorine atom.

Step 6: If we multiply 3 in the reactant (in Cl2) and 2 in the product (in 3NH4Cl), we will get the equal number of atoms as in both the sides. Step 7: Write the resulting equation:

4NH3 + 3Cl2 N2 + 6NH4Cl

Step 8: Now check whether the equation is balanced or not by comparing the atoms. We find that the equation is not balanced yet. As the number of nitrogen atoms are unequal on the two sides.

Balance the nitrogen atom.

Step 9: If we multiply 2 in the reactant (in 4NH3) we will get the equal number of atoms as in products (in N2 and 6NH4Cl) Step 10: Write the resulting equation:

4NH3 + 3Cl2 N2 + 6NH4Cl

Step 11: Now check whether the equation is balanced or not by comparing the atoms. We find that the equation is balanced now.

Step 12: Write down the final balanced equation:

4NH3 + 3Cl2 N2 + 6NH4Cl

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