Answer :

Given:


Wavelength of light, λ = 640.2 nm = 640.2 × 10-9m


Stopping potential, V0 = 0.54 V


Let frequency of light = v


Work function, Φ0 is given by,


Φ0 = hv-eVs


Φ0 = …(1)


Where,


h = Planck’s constant = 6.6 × 10-34Js


c = speed of light = 3 × 108m


λ = wavelength of light


e = charge on each electron = 1.6 × 10-19C


Φ0 =


Φ0 = 2.229 × 10-19J or 1.39 eV


Wavelength of radiation emitted by iron, λ’ = 427.2 nm


λ’ = 4.27.2 × 10-9m


The new stopping potential can be found using equation (1),


Let new stopping potential = v’


By putting the values in equation (1) we get,


Φ0 =




v’ = 1.5 eV


Therefore, the new stopping potential is 1.5 eV.


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