Q. 24.5( 15 Votes )

# Molar volum

Given:

P = 1 atm = 101 kPa

T = 273.15 K

n = 1 mole

V = ?

Explanation: We know that the volume occupied by 1 mole of oxygen gas at STP = 22.4 litres. By using the Ideal Gas Law (PV = nRT) we can obtain the required result.

Wkt…

PV = nRT ---( Ideal Gas Law )

V =

V = 0.0224 m3 = 22.4 litres

V = 22.4 litres

The required volume is 22.4 litres.

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