Answer :

Given:

P = 1 atm = 101 kPa


T = 273.15 K


n = 1 mole


V = ?


Explanation: We know that the volume occupied by 1 mole of oxygen gas at STP = 22.4 litres. By using the Ideal Gas Law (PV = nRT) we can obtain the required result.


Wkt…


PV = nRT ---( Ideal Gas Law )


V =


V = 0.0224 m3 = 22.4 litres


V = 22.4 litres


The required volume is 22.4 litres.


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