Answer :

**Given: Sum of n terms of the G.P. be 316.a = 6, r = 2**

**To Find:**n and a

_{n}

**Formula used:**

where S

_{n = Sum to n terms of G.P,}a = first term,

r = common ratio,

n = number of terms

It is given that the first term a is 6 and common ratio r is 2.

Applying the values in formula we get,

∴ **n = 6**

nth term of G.P is given by -

a_{n} = a r ^{n - 1}

∴ Last term of the G.P = 6th term = ar^{6 - 1} = (6)(2) ^{5} = (6)(32) = 192

**Thus, the last term of the G.P. is 192.**

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