 We have A (–1, 1)

B (0, –3)

C (5, 2)

D (4, 6)

Using the distance formula,

AB = = = = BC = = = = CD= = = = DA = = = = s

We find that AB = CDand BC = DA.

The oppposite pairs of sides are equal for the given quadrilateral.

Consider the diagonals, AC and BD.

AC = = = = BD = = = = Since the diagonals are not equal, the given quadrilateral is not a rectangle.

(This is also visible from the figure since angles are not 90°.)

ABCD is a parallelogram.

The correct option is D.

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