Q. 21 B3.7( 29 Votes )

# Find the su

The given sum is not in GP but we can write it as follows: -

Sum = .6 + .66 + .666 + …to n terms

= 6(0.1) + 6(0.11) + 6(0.111) + …to n terms

taking 6 common

= 6[0.1 + 0.11 + 0.111 + …to n terms]

divide & multiply by 9

= (6/9)[9(0.1 + 0.11 + 0.111 + …to n terms)]

= (6/9)[0.9 + 0.99 + 0.999 + …to n terms]    Since is in GP with

first term(a) = 1/10

common ratio(r) = 10 - 2/10 - 1 = 10 - 1 = 1/10

We know that

Sum of n terms = (As r<1)

putting value of a & r    Hence, Sum Rate this question :

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