Answer :

We have A (2, 1)


B (1, –2)


P (x, y)


Using the distance formula,


AP =


=


=


BP =


=


=


=


Since P is equidistant from A and B


AP = BP


=


Squaring both sides, we get


x2 +y2 – 4x – 2y + 5 = x2 +y2 – 2x + 4y + 5


2x + 6y = 0


or x + 3y = 0


The correct option is A.

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