Q. 9

# Expand using Binomial Theorem We know that- Hence    = a4 + 4a3b + 6a2b2 + 4ab3 + b4

Thus, (a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4 …(1)

Putting , we get-  …(2)

Now Solving separately

From (1)

(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4

putting a = 1 & b = (x/2), we get-   we know that-

(a + b)3 = a3 + 3a2b + 3ab2 + b3

putting a = 1 & b = (x/2), we get-  Substituting the value of in (2), we get-     Thus, Rate this question :

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