# Find a, b and n in the expansion of (a + b)n if the first three terms of the expansion are 729, 7290 and 30375, respectively.

We know that- So first 3 terms are Also, it is given that their value are 729, 7290 and 30375

Therefore, …(1) …(2) …(3)

Dividing (1) by (2)      …(4)

Dividing (2) by (3)       …(5)

Dividing (4) by (5)   12(n-1) = 10n

12n-12 = 10n

2n = 12

n = 12/2

n = 6

Putting n = 6 in (1)

an = 729

a6 = 729

a6 = (3)6

a = 3

Putting a = 3, n = 6 in (5)  6b = 30

b = 30/6

b = 5

Thus, a = 3, b = 5 and n = 6.

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