# Find the interval

It is given that f(x) =

Then, f’(x) =0

3x6 - 3 = 0

x6 = 1

x = 1

Now, the points x =1 and x = - 1 divide the real line into three disjoint intervals

( - ∞, - 1), ( - 1,1) and (1,∞).

In interval ( - ∞, - 1) and (1,∞) when x < - 1 and x > 1 then f’(x) >0

Therefore, when x < - 1 and x > 1, f is increasing.

And, in interval ( - 1,1) when - 1< x < 1 then f’(x) < 0.

Therefore, when - 1 < x < 1, f is decreasing.

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