Answer :

It is given that f(x) =


Then, f’(x) =0


3x6 - 3 = 0


x6 = 1


x = 1


Now, the points x =1 and x = - 1 divide the real line into three disjoint intervals


( - ∞, - 1), ( - 1,1) and (1,∞).


In interval ( - ∞, - 1) and (1,∞) when x < - 1 and x > 1 then f’(x) >0


Therefore, when x < - 1 and x > 1, f is increasing.


And, in interval ( - 1,1) when - 1< x < 1 then f’(x) < 0.


Therefore, when - 1 < x < 1, f is decreasing.


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