Answer :

It is given that curve is y2 = 4x.

Differentiating with respect to x, we get,





Now, the slope of the normal at point (1,2) is


Therefore, Equation of the normal at (1,2) is y - 2 = - 1(x – 1)


y - 2 = - x + 1


x + y - 3 = 0


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