# The points on the

It is given that the equation of the curve is 9y2 = x3

Differentiating w.r.t. x, we get,

The slope of the normal to the given curve at point (x1,y1) is

Then, the equation of the normal to the curve at (x1,y1)is

y – y1 =

Now, it is given that the normal makes equal intercepts with the axes.

Thus, we get,

…………………….(1)

Since, the point (x1,y1)lies on the curve …………(2)

From (1) and (2), we get

Now putting the value of x1 in (2), we get

Therefore, the required points are

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