Q. 244.4( 15 Votes )

# The points on the

Answer :

It is given that the equation of the curve is 9y2 = x3

Differentiating w.r.t. x, we get,  The slope of the normal to the given curve at point (x1,y1) is Then, the equation of the normal to the curve at (x1,y1)is

y – y1 =     Now, it is given that the normal makes equal intercepts with the axes.

Thus, we get,   …………………….(1)

Since, the point (x1,y1)lies on the curve …………(2)

From (1) and (2), we get  Now putting the value of x1 in (2), we get   Therefore, the required points are Rate this question :

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