Q. 244.4( 15 Votes )
The points on the
Answer :
It is given that the equation of the curve is 9y2 = x3
Differentiating w.r.t. x, we get,
The slope of the normal to the given curve at point (x1,y1) is
Then, the equation of the normal to the curve at (x1,y1)is
⇒ y – y1 =
⇒
⇒
⇒
⇒
Now, it is given that the normal makes equal intercepts with the axes.
Thus, we get,
⇒
⇒
⇒ …………………….(1)
Since, the point (x1,y1)lies on the curve …………(2)
From (1) and (2), we get
Now putting the value of x1 in (2), we get
Therefore, the required points are
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
Find the equation
RD Sharma - Volume 1Find the equation
Mathematics - Board PapersFind the equation
RD Sharma - Volume 1Find the equation
RD Sharma - Volume 1Find the equation
RD Sharma - Volume 1Find the equation
RD Sharma - Volume 1Find the equation
RD Sharma - Volume 1Find the conditio
Mathematics - Exemplar