Answer :

It is given that the equation of the curve is 9y2 = x3


Differentiating w.r.t. x, we get,




The slope of the normal to the given curve at point (x1,y1) is



Then, the equation of the normal to the curve at (x1,y1)is


y – y1 =






Now, it is given that the normal makes equal intercepts with the axes.


Thus, we get,




…………………….(1)


Since, the point (x1,y1)lies on the curve …………(2)


From (1) and (2), we get




Now putting the value of x1 in (2), we get





Therefore, the required points are

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Find the equationRD Sharma - Volume 1

Find the equationMathematics - Board Papers

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the equationRD Sharma - Volume 1

Find the conditioMathematics - Exemplar