Answer :

It is given that the equation of curve is 2y + x2 = 3


Differentiating w.r.t. x, we get,





The slope of the normal to the given curve at point (1,1) is



Then, the equation of the normal to the curve at (1,1) is


y – 1 =1(x - 1)


y - 1 = x – 1


x – y = 0

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