Q. 24.5( 23 Votes )

Show that the fun

Answer :

It is given that f(x) =

Then, f’(x) =

Now, f’(x) = 0

⇒ 1 - logx =0

⇒ log x =1

⇒ log x = log e

⇒ x = e

Now, f’’(x) =

Now, f’’(e)=

Therefore, by second derivative test, f is the maximum at x = e.

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