Answer :

It is given that f (x) = cos2 x + sin x, x [0, π]

f’(x) = 2cosx( - sinx) + cosx

= - 2sinxcosx + cosx

Now, if f’(x) = 0

2sinxcosx = cosx

cosx(2sinx - 1)=0

sin x = or cosx = 0

x =

Now, evaluating the value of f at critical points x = and x = and at the end points of the interval [0,π], (ie, at x = 0 and x =π), we get,



f(π)=cos2π + sinπ = ( - 1)2 + 0 =1


Therefore, the absolute maximum value of f is occurring at x = and the absolute minimum value of f is 1 occuring at x =1, and π.

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