Answer :

We have equation as:

|1-i|x = 2x

|z| denotes the modulus function

If z = x + i y, then |z| = √(x+ y2)

For 1 - i, |1 - i| is given by,

|1 - i| = √(12 + (-1)2 ) = √2


x/2 = 2 x


On equating powers, we get:



x = 2x


2x - x = 0


x = 0


Hence, for the given solution 0 is the only integral solution.

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