Answer :

Clearly, No of houses are in AP and


Given,


First term, a = 1


common difference d = 1


According to given statement: S1 to x- 1 = S(x+1) to 49
Sx+1 to 49 = S49 – Sx and S1 to x- 1 = Sx- 1


Since the sum of n terms is Sn =


Where,


a = First term of AP
d = Common difference of AP
and no of terms is ‘n’


Applying given condition:


S1 to x- 1 = S(x+1) to 49
Sx- 1 = S49 – Sx
Sx- 1 = S49 – Sx


(x - 1)(x) = 49(50) - x(x+1)
x2 – x = 49(50) – x2 -x
2x2 = 49 × 50
x2 = 49 × 25
x = 35 and x = -35
Here since the x is a number between 1 to 49,
x = 35.


Hence, The value of x is 35.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

A sum of 280 is tRajasthan Board Mathematics

If the sum of theRajasthan Board Mathematics

Find the sum of aRajasthan Board Mathematics

Find the sum of tRajasthan Board Mathematics

Find the sum of tRajasthan Board Mathematics

Find the sum of tRajasthan Board Mathematics

Find the sum of tRajasthan Board Mathematics

Find the number oRajasthan Board Mathematics

The first term anRajasthan Board Mathematics

If the sum of n tRajasthan Board Mathematics