Q. 12

In the figure 5.7

Answer :

From the figure above it can be clearly seen that,


BDS + SDC = 180° [ Angles made on straight line]


BDS + 80° = 180°


BDS = 100°


Now, ABC = BDS = 100° [Alternate angles are equal]


Now from triangle ABC


Sum of interior angles of a triangle = 180°


ABC + ACB + BAC = 180°


100° + 30° + BAC = 180°


BAC = 50°


Y = BAC = 50°


As AC || PQ and thus alternate angles are equal.


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