# Find the sum of f

Required arithmetic progression is 1, 2, 3, …, 1000
Here, first term a= 1 and common difference d = 1.

Since the sum of n terms is
Sn =

Where,

a = First term of AP
d = Common difference of AP
and no of terms is ‘n’

S1000 =

= 500 [ 2 + 999]

= 500 × 1001
= 500500

Hence, Sum of first 1000 positive integers is 500500.

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