Answer :

Required arithmetic progression is 1, 2, 3, …, 1000

Here, first term a= 1 and common difference d = 1.

Since the sum of n terms is

S_{n =}

Where,

a = First term of AP

d = Common difference of AP

and no of terms is ‘n’

S_{1000 =}

= 500 [ 2 + 999]

= 500 × 1001

= 500500

Hence, Sum of first 1000 positive integers is 500500.

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