Required arithmetic progression is 1, 2, 3, …, 1000
Here, first term a= 1 and common difference d = 1.
Since the sum of n terms is
a = First term of AP
d = Common difference of AP
and no of terms is ‘n’
= 500 [ 2 + 999]
= 500 × 1001
Hence, Sum of first 1000 positive integers is 500500.
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