Q. 4

If α, β, are the A. 0

B. –1

C. 1

D. 2

Answer :

When we compare the above quadratic equation with the generalized one we get,

ax2 + bx + c = 0


a = 1


b = -p


c = -p-c


Sum of zeroes = -b/a


= - (-p) / 1


α + β = p …………………………... (i)


Product of Zeroes = c/a


αβ = - (p + c) …………………… (ii)


Now from LHS we have,


(α + 1)(β + 1) = αβ + α + β + 1


From (i) and (ii) we have the values of αβ and (α + β)


(α + 1)(β + 1) = - (p + c) + p + 1


= - p – c + p + 1


= c + 1


Given (α + 1) (β + 1) = 0


c + 1 = 0


c = -1


So the correct answer is B [-1].

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