Q. 21 A5.0( 1 Vote )

# Solve the following quadratic equations by using Shridharacharya Quadratic Formula:p2x2 + (p2 – q2)x – q2 = 0

When we compare the above quadratic equation with the generalized one we get,

ax2 + bx + c = 0

a = p2

b = (p2 – q2)

c = – q2

There is one formula developed by Shridharacharya to determine the roots of a quadratic equation which is as follows:

Before putting the values in the formula let us check the nature of roots by b2 – 4ac >0

((p2 – q2)) 2 – (4 × p × – q2)

(p4 –2 p2 q2 + q4) - (-4p2q2)

p4 –2 p2 q2 + q4 + 4p2q2

(p4 + 2 p2 q2 + q4)

((p2 + q2)) 2

Now let us put the values in the above formula

Solving with positive value first,

x = q2 / p2

Solving with negative value second,

x = -1

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