Q. 184.8( 4 Votes )

Solve the quadrat

Answer :

x2 + 4x – 5 = 0

x2 + 4x = 5


Now by taking half of the coefficient of x and then squaring it and adding on both LHS and RHS sides.


Coefficient of x = 4


Half of 4 = 2


Squaring the half of 4 = 4


x2 + 4x + 4= 5 + 4


(x + 2)2 = 9


On simplifying both RHS and LHS we get an equation of following form,


(x ± A)2 = k2


Taking square root of both sides,


(x + 2) = ±3


Solving first with positive sign of 3,


x + 2 = 3


x = 3 – 2


x = 1


Solving with negative sign of 3,


x + 2 = -3


x = -3 – 2


x = -5


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