Q. 105.0( 2 Votes )

The LCM of expres A. x + 1

B. (x2 – 1)(x + 1)

C. (x – 1)(x + 1)2

D. (x2 – 1)(x + 1)2

Answer :

Let us factorize x2 +2x + 1

But x2 +2x + 1 is a perfect square and it can be expressed as (x + 1)2


u(x) = x2 +2x + 1


u(x) = x2 +x + x + 1


u(x) = x(x + 1) +1(x + 1)


u(x) = (x + 1) (x + 1)


Let v(x) = x2 – 1


= (x + 1) (x – 1)


So by comparing both polynomials, LCM is = (x1) (x+1)2


So the correct answer is C [(x – 1)(x + 1)2].

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