Answer :
It is mentioned in the question that that on dividing 2053 by the required number there is a remainder of 5 which means that 2053 - 5 = 2048 is exactly divisible by required number . In the similar manner,
967 - 7 = 960 the required number is the largest number satisfying the above property.
Therefore, it is the HCF of 2048 & 960
2048 = 64 × 32
= 26 × 25
= 211
960 = 5 × 2 × 2 × 2 × 2 × 2 × 2 × 3
So for finding the HCF we may write as follows:
Common Factor Least Power
2 6
So HCF = 26
= 64
HCF of 2048 & 960 is 64
Hence required number is 64
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
Find the HCF and
Rajasthan Board MathematicsFind the HCF and
Rajasthan Board MathematicsIf LCM of a</i
Rajasthan Board MathematicsIf n is a rationa
Rajasthan Board MathematicsExpress the follo
Rajasthan Board MathematicsExpress the follo
Rajasthan Board MathematicsExpress the follo
Rajasthan Board MathematicsExpress the follo
Rajasthan Board MathematicsIf two numbers ar
Rajasthan Board MathematicsThe HCF (Highest
Rajasthan Board Mathematics