Q. 295.0( 5 Votes )

# The radius of a c Given radius of circle OQ = OR = √2 cm

Length of chord, QR = 2 cm

In ΔOQR,

OQ2 + OR2 = (√2)2 + (√2)2

= 2 + 2

= 4

= (QR)2

OQ2 + OR2 = QR2

ΔOQR is a right angled triangle at QOR.

We know that angle at the centre is double the angle on the remaining part of the circle.

⇒∠QOR = 2QPR

90° = 2QPR

QPR = 45°

The angle subtended by the chord at the point in major segment is 45°.

Hence proved

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