Q. 64.0( 4 Votes )

In a trapezium ABCD, AB || CD and its diagonals meet at point O. If AB = 6 cm and DC = 3 cm then the ratio of the areas of ΔAOB and ΔCOD will be:
A. 4 : 1

B. 1 : 2

C. 2 : 1

D. 1 : 4

Answer :


In ΔAOB and ΔCOD,


O = O |vertically opposite angle


As AB||CD


BAO = OCD |alternate s


OBA = ODC |alternate s


Thus, ΔAOB~ΔCOD


For two similar triangles, the ratio of their area is equal to the square of the ratio of their corresponding sides.



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