Answer :
Given,
AD = x + 4
DB = x + 3
AE = 2x – 1
EC = x + 1
In ΔADE & ΔABC,
DE||BC
By BPT,
Putting the values,
(x + 1) = (2x – 1)(x + 3)
⇒ x2 + 5x + 4 = 2x2 + 5x – 3
⇒ x2 + 4 = 2x2 – 3
⇒ x2 = 7
⇒ x = √7
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