Answer :

The distance of a point with position vector from the plane is .

The position vector of point (1,1,p) is given as -



The position vector of point (-3,0,1) is given as -



It is given that the points (1,1,p) and (-3,0,1) are equidistant from the plane






20 - 12p = 8


20 - 12p = 8 or, 20 - 12p = -8


12p = 12 or, 12p = 28


p = 1 or, p = 7/3


us, the possible values of p are 1 and 7/3.


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