Answer :
The equation of any line parallel to the y – axis is of the form
x = a -------- (1)
The two given lines are
x – 7y + 5 = 0 ---------(2)
3x + y = 0 ------- (3)
Multiply eq (2) with 3 and subtract eq(3) from it to get,
3x - 21y + 15 - 3x - y = 0
-22y = -15

Put value of y in eq(3) to get,



Thus,
is the point of intersection of lines (2) and (3).
Since, line x = a pass through point a =
Therefore, the required equation of the line is x =
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