Answer :
The equation of the line joining the points (cosƟ, sinƟ) and (cosɸ, sinɸ) is given by
⇒ y(cosɸ-cosƟ) – sinƟ(cosɸ-cosƟ) = x(sinɸ-sinƟ) – cosƟ(sinɸ-sinƟ)
⇒ x(sinƟ- sinɸ) + y(cosɸ- cosƟ) + cosƟsinɸ - cosƟsinƟ – sinƟcosɸ + sinƟcosƟ = 0
⇒ x(sinƟ- sinɸ) + y(cosɸ- cosƟ) + sin(ɸ-Ɵ) = 0
Ax + By + C = 0, where A = sinƟ- sinɸ, B = cosɸ- cosƟ, and C = sin(ɸ-Ɵ)
It is known that the perpendicular distance (d) of the line Ax + By + C = 0 from a point
(x1, y1) is given by
Thus, the perpendicular distance (d) of the given line from point (x1, y1) =(0,0) is
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
<span lang="EN-US
RS Aggarwal - MathematicsThe distance betw
RD Sharma - Mathematics<span lang="EN-US
RS Aggarwal - MathematicsFind the equation
RD Sharma - MathematicsFind the equation
RD Sharma - MathematicsArea of the trian
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - MathematicsA point equidista
RD Sharma - Mathematics