Q. 214.3( 31 Votes )

Find equati

Answer :

The equations of the given lines are


9x + 6y – 7 = 0 ---------------- (1)


3x + 2y + 6 = 0 ---------------- (2)


Let P (h, k) be the arbitrary point that is equidistant from (1) and (2).


The perpendicular distance of P(h, k) from line (1) is given by





The perpendicular distance of P(h, k) from line (2) is given by




Since, P (h, k) is equidistant from lines (1) and (2),


Thus,





or


So, when is not possible as


which is not at all possible


And when


9h + 6k – 7 = -9h – 6k – 18


18h + 12k +11 = 0


Therefore, the required equation of the line is 18h + 12k +11 = 0.


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