Answer :
The equation of the given lines are
y = m1x + c1 ---------(1)
y = m2x + c2 ---------(2)
y = m3x + c3 ---------(3)
On subtracting equation (1) from (2), we get,
0 = (m2 - m1)x + (c2 – c1)
⇒ (m2 - m1)x = (c2 – c1)
⇒ x =
On substituting this value of x in (1), we get,
Thus,
is the point of intersection of lines (1) and (2).
It is given that lines (1), (2) and (3) are concurrent.
Thus, the point of intersection of lines (1) and (2) will also satisfy equation (3).
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
The equation of t
RD Sharma - MathematicsFind the equation
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - MathematicsFind the equation
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - MathematicsFind the equation
RD Sharma - MathematicsFind the equation
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - Mathematics