Answer :

(i)-(d), (ii)-(a), (iii)-(b), (iv)-(e), (v)-(f)


(i)-(d)FeSO4.7H2O, Fe2+ has 3d6 electronic configuration. The complementary colour is pale green


(ii)-(a) NiCl2.4H2O ,Ni2+ has 3d8 electronic configuration. The complementary colour is green


(iii)-(b)MnCl2.4H2O , Mn2+ has 3d5 electronic configuration. The complementary colour is light pink


(iv)-(e)CoCl2.6H2O, Co2+ has 3d7 electronic configuration. The complementary colour is pink


(v)-(f) Cu2Cl2is colourless, Cu+ has 3d10 electronic configuration. It has a fully filled d orbital without no unpaired electrons to get excited and absorb visible light. So, Cu2Cl2 is colourless.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USChemistry - Board Papers

<span lang="EN-USChemistry - Board Papers

When an oxide of Chemistry - Exemplar

Identify compoundChemistry - Exemplar

A violet compoundChemistry - Exemplar