Answer :

Photoelectric equation


K. Emax = hv – hv0 ……………………………………….equ.01


Where K.Emax = maximum kinetic energy of the photoelectron


h = plank’s constant


v = frequency of photon


v0 = threshold frequency


K. Emax = 1/2 mv2 max ........................................equ.02


Where ‘m’ = mass of the electron = 9.1 × 10-31 kg


Vmax = maximum speed of photoelectrons


From equ.01 and equ.02


1/2 mv2 max = hv - hv0


v0 = v - 1/2 mv2 max / h



v0 = 7.21 × 1014 –2.47 × 1014


v0 = 4.74 × 1014 Hz


Threshold frequency for photoemission is equal to 4.74 × 1014 Hz.


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